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 2025.gada matemātikas optimālā līmeņa eksāmena risinājums

  • 2025.gada matemātikas optimālā līmeņa eksāmena risinājums

     

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ID number:439802
 
Author:
Evaluation:
Published: 16.09.2025.
Language: Latvian
Level: Secondary school
Literature: 1 units
References: Used
Extract

1. uzdevums (2 punkti)
Aprēķini.
1.1. (1 punkts) 16^1/2 = v(16) = 4
1.2. (1 punkts) log3^81 = 4
3^x=81

2. uzdevums (4 punkti)
2.1. (1 punkts) 4v(3) + 4v(3)=
A 8v(6) B 16v(3) C 2 4v(6) D 2 4v(3)
2.2. (1 punkts) Iznes reizinātāju pirms saknes zīmes.
3v(8a) =2 3v(a)…

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