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ID number:679987
 
Author:
Evaluation:
Published: 22.12.2010.
Language: Latvian
Level: College/University
Literature: n/a
References: Not used
Extract

Koeficientu pārbaude

δ11+δ12=δ1S
256/3EI+240/3EI=4/6EI(4*4+4*2*2+0)+10/15EI(4*14+4*4*9+4*4)
496/3EI=128/6EI+432/3EI
496/3EI=496/3EI (Sakrīt, tātad δ11 un δ12 aprēķināti pareizi)

δ21+ δ21=δ2S
240/3EI+450/3EI=10/15EI(10*14+4*5*9+0*4)+5/15EI(5*5+4*2.5*2.5+0)
690/3EI=640/3EI+50/3EI
690/3EI=690/3EI (Sakrīt, tātad δ21 un δ21 aprēķināti pareizi)

Brīvo locekļu pārbaude

∆1P+∆2P=∆SP
4156/3EI+5382,5/3EI=10/15EI(14*97+4*9*97+4*97)-2/6EI(5)*4+4*3*25+2*0)-5/15EI(5*50+4*2,5*18,75+0)
9538,5/3EI=10476/3EI-500/3EI-437,5/3EI
9538,5/3EI=9538,5/3EI (Sakrīt. Tātad brīvie locekļi ir aprēķināti pareizi).…

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