Sijas aprēķins / Summaries, Notes / ID: 271864

Author: Sandis Leikums (3)

Evaluation:

Published: 13.02.2020.

Language: Latvian

Level: College/University

Literature: n/a

References: Not used

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Trešajā šķēlumā 3 – 3 (4 ≤ x3 < 6,5 m):
Q(x3) = - P1 + RA - q1×(x3 - 4)
Q3(4) = - 8 + 9.65 - 2×(4 - 4) = 1.65 (kN)
Q3(6.50) = - 8 + 9.65 - 2×(6.5 - 4) = -3.35 (kN)

Pie x = 4,83 ir kritiskais punkts, tur var būt kritiskais spēka moments Mkrit
x = 4.83

M(x3) = - P1×(x3) + RA×(x3 - 1.5) - q1×(x3 - 4)2/2
M3(4) = - 8×(4) + 9.65×(4 - 1.5) - 2×(4 - 4)2/2 = -7.88 (kNm)
M3(6.50) = - 8×(6.50) + 9.65×(6.50 - 1.5) - 2×(6.50 - 4)2/2 = -10 (kNm)

Ir jāpārbauda kritiskais punkts ir x = 4,83 m:
M3(4.83) = - 8×(4.83) + 9.65×(4.83 - 1.5) - 2×(4.83 - 4)2/2 = -7.19 (kNm)
Ceturtajā šķēlumā 4 – 4 (6,5 ≤ x4 < 8,25 m):
Q(x4) = - P1 + RA - q1×(6.5 - 4) + RB
Q4(6.50) = - 8 + 9.65 - 2×(6.5 - 4) + 3.35 = 0 (kN)
Q4(8.25) = - 8 + 9.65 - 2×(6.5 - 4) + 3.35 = 0 (kN)
…

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Summaries, Notes

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