Kursa darbs

j) Aprēkinam patērētāja linijas spriegumus:

Uab = Ua01 − Ub01 = 51.02+j140.12 = 149.12ej69.99° (V)

Ubc = Ub01 − Uc01 = 48.23-j96.92 = 108.257e-j63.54° (V)
Uca = Uc01 – Ua01 = -99.25-j43.2 = 108.244e-j156.48° (V)

k) Aprēkinam sprieguma kritumus linijā

ŮAa = İa*R = (9.423+j4.087)*5 = 47.115+j20.435 = 51.356ej23.45° (V)
ŮBb = İb*R = (4.589-j9.189)*5 = 22.945-j45.945 = 51.356e-j63.46° (V)
ŮCc = İc*R = (-14.012+j5.103)*5 = -70.06+j25.515 = 74.562ej159.99° (V)
…